4x^2-64x+60=0

Solution for 4x^2-64x+60=0 equation:

4x^2-64x+60=0

a = 4; b = -64; c = +60;
Δ = b2-4ac
Δ = -642-4·4·60
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-56}{2*4}=\frac{8}{8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+56}{2*4}=\frac{120}{8}
=15
$